Mr. West is standing on a cliff that is 25 1/5meters above the surface of the ocean. He spots a dolphin that is 2 3/5 meters under the water. What was the total distance from Mr. West to the dolphin?
Accepted Solution
A:
Answer:Total distance from Mr. West to dolphin [tex]=27\frac{4}{5}\ meters[/tex]Step-by-step explanation:Height of cliff on which Mr. West is standing above the surface of ocean =[tex]25 \frac{1}{5} \ meters[/tex]Mr. West spot the dolphin under the water at a depth of = [tex]2\frac{3}{5} \ meters[/tex]∴ Total distance from Mr. West to dolphin=[tex](25 \frac{1}{5}+2\frac{3}{5})\ meters[/tex] Adding mixed numbers[tex](25 \frac{1}{5}+2\frac{3}{5})[/tex]Adding whole numbers first.[tex]=25+2+\frac{1}{5}+\frac{3}{5}\\=27+\frac{1}{5}+\frac{3}{5}[/tex]Adding fractions by taking LCD.[tex]=27+\frac{1+3}{5}\\=27+\frac{4}{5}\\=27\frac{4}{5}\ meters[/tex]